If sides A and B of a triangle have lengths of 5 and 2 respectively, and the angle between them is $\frac{3 π}{8}$ $(3pi)/8$ , then what is the area of the triangle?

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If sides A and B of a triangle have lengths of 5 and 2 respectively, and the angle between them is $\frac{3 π}{8}$ $(3pi)/8$ , then what is the area of the triangle?

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Answer 1 · 2017-01-05T11:29:09

We just need the formula for the area of a triangle give two sides and the angle between them.

Explanation:

The standard formula is $A r e a = \frac{1}{2} b c sin α$ $Area=1/2bc\sin\alpha$ , where $b$ $b$ and $c$ $c$ are the two sides and $α$ $\alpha$ is the angle between them.

So $A r e a = \frac{1}{2} \times 5 \times 2 \times sin (\frac{3 π}{8}) = 4.62$ $Area = 1/2 \times 5 \times 2 \times \sin((3\pi)/8)=4.62$ .

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If sides A and B of a triangle have lengths of 5 and 2 respectively, and the angle between them is $\frac{3 π}{8}$ $(3pi)/8$ , then what is the area of the triangle?

1 Answer

Explanation:

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If sides A and B of a triangle have lengths of 5 and 2 respectively, and the angle between them is $\frac{3 π}{8}$ $(3pi)/8$ , then what is the area of the triangle?