If the endpoints of the diameter of a circle are (7, 8) and (-2, 12), what are the coordinates of the center of the circle?
1 Answer
Feb 11, 2016
centre =
(5/2 , 10 )(52,10)
Explanation:
The centre of the circle is at the mid-point of the diameter. Hence to find coords of centre , find the mid-point of the end points.
hence :
[ 1/2 (x_1 + x_2 ) , 1/2(y_1 + y_2 ) ][12(x1+x2),12(y1+y2)] let
(x_1 , y_1 ) = ( 7 , 8 )color(black)(" and ") (x_2 , y_2 ) =(-2 , 12 )(x1,y1)=(7,8) and (x2,y2)=(−2,12) substitute these values into the formula:
rArr[ 1/2(7-2) , 1/2(8+12 )] = ( 5/2 , 10 )⇒[12(7−2),12(8+12)]=(52,10)