If x= 3, y-12 and z=8, how do you evaluate: $y^{2} \div (3 z) + 2 x$ $y^2div(3z)+2x$ ?

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If x= 3, y-12 and z=8, how do you evaluate: $y^{2} \div (3 z) + 2 x$ $y^2div(3z)+2x$ ?

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Answer 1 · 2017-01-01T17:26:38

$12$ $12$

Explanation:

To evaluate the expression, substitute the given values for x, y and z into it.

$y^{2} \div (3 z) + 2 x may be expressed as follows.$ $y^2÷(3z)+2x" may be expressed as follows."$

$\frac{y^{2}}{3 z} + 2 x$ $(y^2)/(3z)+2x$

and substituting in the given values.

$\frac{y^{2}}{3 z} + 2 x = \frac{{(- 12)}^{2}}{3 \times 8} + (2 \times 3)$ $y^2/(3z)+2x=(-12)^2/(3xx8)+(2xx3)$

$= \frac{144}{24} + 6 \to divide before adding$ $=144/24+6rarr "divide before adding"$

$= 6 + 6 = 12$ $=6+6=12$

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If x= 3, y-12 and z=8, how do you evaluate: $y^{2} \div (3 z) + 2 x$ $y^2div(3z)+2x$ ?

1 Answer

Explanation:

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If x= 3, y-12 and z=8, how do you evaluate: $y^{2} \div (3 z) + 2 x$ $y^2div(3z)+2x$ ?