In the formation of carbon dioxide from carbon monoxide and oxygen, how many liters of carbon monoxide, CO, are needed to react completely with 1/2 mole of oxygen gas at STP? 2 CO (g) + O2(g) → 2 CO2 (g)

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In the formation of carbon dioxide from carbon monoxide and oxygen, how many liters of carbon monoxide, CO, are needed to react completely with 1/2 mole of oxygen gas at STP? 2 CO (g) + O2(g) → 2 CO2 (g)

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Answer 1 · 2016-04-16T15:34:50

Approx. $22.4$ $22.4$ $L$ $L$ of $C \equiv O$ $C-=O$ gas are required.

Explanation:

At constant pressure and temperature, the volume of a gas represents the number of particles. You have given te stoichiometric equation:

$2 C \equiv O (g) + O_{2} (g) \to 2 C O_{2} (g)$ $2C-=O(g) + O_2(g) rarr 2CO_2(g)$ ,

And this equation shows that carbon monoxide reacts with molecular oxygen in a $2 : 1$ $2:1$ ratio. But at $S T P$ $STP$ , the volume of half a mole $O_{2}$ $O_2$ is $11.2 \cdot L$ $11.2*L$ . And of course we need double the molar quantity, and thus double the volume, of carbon monoxide gas for stoichiometric reaction.

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In the formation of carbon dioxide from carbon monoxide and oxygen, how many liters of carbon monoxide, CO, are needed to react completely with 1/2 mole of oxygen gas at STP? 2 CO (g) + O2(g) → 2 CO2 (g)

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