Question

In triangle ABC, a=6.3. B=9.4, <C=38.3° how do you find side C?

Answer 1

The length of side `c` is approximately 5.9.

Explanation:

You use the Law of Cosines - 'cause it's the LAW!

`c^2=a^2+b^2-2abcostheta`

Soving for `c` gives us the equation

`c=sqrt(a^2+b^2-2abcostheta)`

Here `a=6.3`, `b=9.4`, and `theta=38.3^@`, so

`c=sqrt(6.3^2+9.4^2-2(6.3)(9.4)cos38.3^@)~~5.9`