Is it possible to factor y= 16x^2 -24x + 9 y=16x224x+9? If so, what are the factors?

1 Answer
Jan 11, 2016

(4x-3)(4x-3)(4x3)(4x3)

Explanation:

It is a good idea to try integer coefficients in the factors, since the function itself has all integer coefficients. Since 9 = 3^29=32 and the middle term is negative, it's good to check out factors of the form (ax-3)(bx-3), for some coefficients a and b. Since axax times bxbx must give 16x^216x2, and 16=2^416=24, the coefficients a and b must be powers of 2. Trying possibilities, we see it works for a=4 and b=4. That is, for this choice of powers of 2, we get the middle term, namely -24x.