Is it possible to factor $y = 2 x^{2} - 16 x + 32$ $y=2x^2-16x+32$ ? If so, what are the factors?

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Answer 1 · 2018-04-15T00:36:21

$x = 4$ $x=4$

$y = 2 x^{2} - 16 x + 32$ $y=2x^2-16x+32$

$y = 2 (x^{2} - 8 x + 16)$ $y=2(x^2-8x+16)$

$y = 2 {(x - 4)}^{2}$ $y=2(x-4)^2$

Therefore, the factor is $x = 4$ $x=4$ . Note that this is a double root

Is it possible to factor y=2x2−16x+32y=2x^2-16x+32 ? If so, what are the factors?