Is it possible to factor $y= 2x^2 + x - 1$ ? If so, what are the factors?

Question

1520 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2015-12-06T07:39:46

$y=(x+1)(2x-1)$

$y=2x^2+x-1$ is a quadratic equation with the form $ax^2+bx+c$ , where $a=2, b=1, c=-1$

Use the AC method to factor this equation.

Multiply $a$ times $c$ .

$2xx-1=-2$

Determine two numbers that when added equal $1$ , and when multiplied equal $-2$ . The numbers $2$ and $-1$ meet the criteria.

Rewrite the expression with $2x$ and $-x$ in place of $x$ .

$2x^2+2x-x-1$

Group the first two terms and the second two terms.

$(2x^2+2x)-(x+1)$

Factor out the GCF $2x$ from the first pair of terms.

$2x(x+1)-(x+1)$

Factor out $(x+1)$ .

$(x+1)(2x-1)$

$y=(x+1)(2x-1)$

Is it possible to factor y= 2x^2 + x - 1 y= 2x^2 + x - 1 ? If so, what are the factors?