Is it possible to factor $y= 2x^3-50x$ ? If so, what are the factors?

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Answer 1 · 2018-03-09T15:40:56

$y=2x(x+5)(x-5)$

Well, we can already see that both terms have an $x$ , and are a multiple of $2$ so we can take $2x$ out to get $y=2x(x^2-25)$

Difference of two squares tell us that $a^2-b^2=(a+b)(a-b)$ .

$x^2-25=(x+5)(x-5)$ since $x^2=(x)^2$ and $25=5^2$

This gives us $y=2x((x+5)(x-5))=2x(x+5)(x-5)$

Is it possible to factor y= 2x^3-50x y= 2x^3-50x ? If so, what are the factors?