Is it possible to factor $y = 4 x^{2} - 49$ $y=4x^2-49$ ? If so, what are the factors?

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Answer 1 · 2015-12-10T04:08:44

$(2 x - 7), (2 x + 7)$ $color(blue)((2x-7) , (2x+7)$ are the factos of the expression.

$y = 4 x^{2} - 49$ $y=4x^2-49$

The expression can be re written as:
$y = {(2 x)}^{2} - 7^{2}$ $y=(2x)^2-7^2$ , this is of the below format:

$a^{2} - b^{2} = (a - b) (a + b)$ $color(blue)(a^2-b^2=(a-b)(a+b)$

So,
$y = {(2 x)}^{2} - 7^{2} = (2 x - 7) (2 x + 7)$ $y=(2x)^2-7^2 = color(blue)((2x-7)(2x+7)$

$(2 x - 7) (2 x + 7)$ $color(blue)((2x-7)(2x+7)$ is the factorised form of the expression.

Is it possible to factor y=4x2−49y=4x^2-49 ? If so, what are the factors?