Is it possible to factor $y = 4 x^{2} + 4 x + 1$ $y=4x^2+4x+1$ ? If so, what are the factors?

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Answer 1 · 2016-03-28T11:28:10

$y = (2 x + 1) (2 x + 1)$ $y=(2x+1)(2x+1)$

$y = 4 x^{2} + 4 x + 1 or y = {(2 x + 1)}^{2} or y = (2 x + 1) (2 x + 1)$ $y=4x^2+4x+1 or y=(2x+1)^2 or y = (2x+1)(2x+1)$ [ans]

Is it possible to factor y=4x^2+4x+1y=4x2+4x+1y=4x^2+4x+1? If so, what are the factors?