Is it possible to factor $y=6x^2+17x+12$ ? If so, what are the factors?

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Answer 1 · 2018-07-25T20:20:57

$y=(2x+3)(3x+4)$

Given quadratic polynomial:

$6x^2+17x+12$

$=6x^2+9x+8x+12$

$=3x(2x+3)+4(2x+3)$

$=(2x+3)(3x+4)$

$\therefore y=(2x+3)(3x+4)$

Is it possible to factor y=6x^2+17x+12 y=6x^2+17x+12 ? If so, what are the factors?