Is it possible to factor $y = 9 x^{2} - 48 x + 64$ $y=9x^2-48x+64$ ? If so, what are the factors?

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Is it possible to factor $y = 9 x^{2} - 48 x + 64$ $y=9x^2-48x+64$ ? If so, what are the factors?

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Answer 1 · 2016-08-25T14:35:44

Yes

Explanation:

If you are having a problem factorising a quadratic by inspection then use the formula
$x = \frac{- b \pm \sqrt{b^{2} - 4 a c}}{2 a}$ $x=(-b+-sqrt(b^2-4ac))/(2a)$

In this example the discriminant $b^{2} - 4 a c$ $b^2-4ac$ =0
So the factors are the same
$x = \frac{48}{2 \cdot 9} = \frac{8}{3}$ $x=48/(2*9)=8/3$
So the two factors are both $3 x - 8$ $3x-8$

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Is it possible to factor $y = 9 x^{2} - 48 x + 64$ $y=9x^2-48x+64$ ? If so, what are the factors?

1 Answer

Explanation:

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Is it possible to factor y=9x2−48x+64y=9x^2-48x+64? If so, what are the factors?

1 Answer

Explanation:

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Is it possible to factor $y = 9 x^{2} - 48 x + 64$ $y=9x^2-48x+64$ ? If so, what are the factors?