Is it possible to factor $y=x^2 - 8x + 16$ ? If so, what are the factors?

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Answer 1 · 2016-03-09T10:40:47

$" "y=x^2-8x+16 = (x-4)(x-4)$

Given: $" "y=x^2-8x+16$

Observe that $4xx4 = 16" and "4+4=8$

The $8x$ is negative so the $4+4=8" must be "-4-4=-8$
This also works for $(-4)xx(-4)=+16$

$" "y=x^2-8x+16 = (x-4)(x-4)$

Is it possible to factor y=x^2 - 8x + 16y=x^2 - 8x + 16? If so, what are the factors?