Is it possible to factor $y = x^{3} - 3 x^{2} - 4 x + 12$ $y=x^3 - 3x^2 - 4x + 12$ ? If so, what are the factors?

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Is it possible to factor $y = x^{3} - 3 x^{2} - 4 x + 12$ $y=x^3 - 3x^2 - 4x + 12$ ? If so, what are the factors?

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Answer 1 · 2016-01-20T13:35:10

(x - 3 )(x - 2 )(x + 2 )

Explanation:

By factorising in pairs :

$[x^{2} (x - 3)] + [- 4 (x - 3)]$ $[ x^2 ( x - 3 ) ] + [ - 4 ( x - 3 ) ]$

ie $x^{2} (x - 3) - 4 (x - 3)$ $x^2 (x - 3 ) - 4 ( x - 3 )$

now there is a common factor of (x - 3 )

$(x - 3) (x^{2} - 4)$ $(x - 3 )(x^2 - 4 )$

$x^{2} - 4$ $x^2 - 4$ is a difference of 2 squares.

and $x^{2} - 4 = (x - 2) (x + 2)$ $x^2 - 4 = ( x - 2 )(x + 2 )$

$\Rightarrow x^{3} - 3 x^{2} - 4 x + 12 = (x - 3) (x - 2) (x + 2)$ $rArr x^3 -3x^2 - 4x + 12 = (x - 3 )(x - 2 )(x + 2 )$

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Is it possible to factor $y = x^{3} - 3 x^{2} - 4 x + 12$ $y=x^3 - 3x^2 - 4x + 12$ ? If so, what are the factors?

1 Answer

Explanation:

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Math

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Is it possible to factor y=x3−3x2−4x+12y=x^3 - 3x^2 - 4x + 12 ? If so, what are the factors?

1 Answer

Explanation:

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Impact of this question

Is it possible to factor $y = x^{3} - 3 x^{2} - 4 x + 12$ $y=x^3 - 3x^2 - 4x + 12$ ? If so, what are the factors?