Magnesium will burn in oxygen to form magnesium oxide as represented by the following equation 2Mg(s) + O2(g) -> 2MgO(s) What mass of magnesium will react with 498.1 ml of oxygen at 145.2 degrees Celsius and 0.927 atm?

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Answer 1 · 2017-05-20T09:41:09

Approx. $300*mg$

We use the Ideal Gas Equation to access the molar quantity of dioxygen gas............

$n=(PV)/(RT)=(0.927*atmxx0.4981*L)/(0.0821*(L*atm)/(K*mol)xx418.4*K)=1.34xx10^-2*mol$ .

Given the stoichiometric equation..........

$Mg(s) + O_2(g) rarr MgO(s)$

There are $1.34xx10^-2*molxx24.31*g*mol^-1=??*g$ metal required for stoichiometric equivalence.