Make #x# the subject of #y= ( x - 4) ^ { 2} + 6#?
1 Answer
Explanation:
#y=(x-4)^2 +6#
#(x-4)^2=y-6#
Take the square root of both sides:
#sqrt((x-4)^2) = sqrt(y-6)#
#x-4= +- sqrt(y-6)#
Add
#x= +-sqrt(y-6) +4#
#y=(x-4)^2 +6#
#(x-4)^2=y-6#
Take the square root of both sides:
#sqrt((x-4)^2) = sqrt(y-6)#
#x-4= +- sqrt(y-6)#
Add
#x= +-sqrt(y-6) +4#