Points A and B are at (2 ,5 ) and (6 ,2 ), respectively. Point A is rotated counterclockwise about the origin by (3pi)/2 and dilated about point C by a factor of 1/2 . If point A is now at point B, what are the coordinates of point C?

2 Answers
Jun 8, 2018

color(red)("Coordinates of " C (7,6)

Explanation:

A(2,5), B(6,2), "rotation " (3pi)/2, "dilation factor" 1/2

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New coordinates of A after (3pi)/2 counterclockwise rotation

A(2,5) rarr A' (5,-2)

vec (BC) = (1/2) vec(A'C)

b - c = (1/2)a' - (1/2)c

(1/2)c = -(1/2)a' + b

(1/2)C((x),(y)) = -(1/2)((5),(-2)) + ((6),(2)) = ((7/2),(3))

color(red)("Coordinates of " 2 *C ((7/2),3) = C(7,6)

Jun 8, 2018

C=(7,6)

Explanation:

"under a counterclockwise rotation about the origin of "(3pi)/2

• " a point "(x,y)to(y,-x)

A(2,5)toA'(5,-2)" where A' is the image of A"

vec(CB)=color(red)(1/2)vec(CA')

ulb-ulc=1/2(ula'-ulc)

ulb-ulc=1/2ula'-1/2ulc

1/2ulc=ulb-1/2ula'

color(white)(1/2ulc)=((6),(2))-1/2((5),(-2))

color(white)(1/2ulc)=((6),(2))-((5/2),(-1))=((7/2),(3))

ulc=2((7/2),(3))=((7),(6))

rArrC=(7,6)