Points A and B are at (3 ,5 ) and (6 ,1 ), respectively. Point A is rotated counterclockwise about the origin by (3pi)/2 and dilated about point C by a factor of 3 . If point A is now at point B, what are the coordinates of point C?

1 Answer
Jun 8, 2017

The coordinates of point C=(9/2,-5)

Explanation:

The matrix of a rotation counterclockwise by 3/2pi about the origin is

((0,1),(-1,0))

Therefore, the trasformation of point A is

A'=((0,1),(-1,0))((3),(5))=((5),(-3))

Let point C be (x,y), then

vec(CB)=3 vec(CA')

((6-x),(1-y))=3((5-x),(-3-y))

So,

6-x=3(5-x)

15-3x=6-x

2x=9

x=9/2

and

1-y=3(-3-y)

-9-3y=1-y

2y=-10

y=-5

Therefore,

point C=(9/2,-5)