Points A and B are at (4 ,9 )(4,9) and (6 ,8 )(6,8), respectively. Point A is rotated counterclockwise about the origin by (3pi)/2 3π2 and dilated about point C by a factor of 4 4. If point A is now at point B, what are the coordinates of point C?

1 Answer
Jun 15, 2017

The point C=(10,-8)C=(10,8)

Explanation:

The matrix of a rotation counterclockwise by 3/2pi32π about the origin is

((0,1),(-1,0))

Therefore, the transformation of point A is

A'=((0,1),(-1,0))((4),(9))=((9),(-4))

Let point C be (x,y), then

vec(CB)=4 vec(CA')

((6-x),(8-y))=4((9-x),(-4-y))

So,

6-x=3(9-x)

6-x=36-4x

3x=30

x=10

and

8-y=4(-4-y)

8-y=-16-4y

3y=-24

y=-8

Therefore,

point C=(10,-8)