Points A and B are at (6 ,7 )(6,7) and (7 ,4 )(7,4), respectively. Point A is rotated counterclockwise about the origin by pi/2 π2 and dilated about point C by a factor of 2 2. If point A is now at point B, what are the coordinates of point C?

1 Answer
Aug 10, 2017

The coordinates of point C=(-21,8)C=(21,8)

Explanation:

Point A=((6),(7)) and point B=((7),(4))

The rotation of point A counterclockwise tranforms the point A into

A'=((-7),(6))

Let point C=((x),(y))

The dilatation is

vec(CB)=2vec(CA')

((7),(4))-((x),(y))=2*((-7),(6))-((x),(y)))

Therefore,

7-x=2(-7-x)

7-x=-14-2x

x=-14-7=-21

4-y=2(6-y)

4-y=12-2y

y=12-4=8

The point C=(-21,8)