(R + RCos (2,57 (20)) = 12), How to solve for R?

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(R + RCos (2,57 (20)) = 12), How to solve for R?

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Answer 1 · 2016-03-29T15:10:24

This solution is based on $cos (2.57 \times 20)$ $cos(2.57xx20)$
$R \approx 7.390$ $R~~7.390$ to 3 decimal places
'~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
$R = \frac{12}{1 + cos (2.5720)} \approx 6.003$ $R=12/(1+cos(2.5720)) ~~6.003$ to 3 decimal places

Explanation:

Given: $R + R cos (2.57 (20)) = 12$ $R+Rcos(2.57(20))=12$

Factor out the R giving

$R (1 + cos (2.57 (20)) = 12$ $R(1+cos(2.57(20))=12$

Divide both sides by $(1 + cos (2.57 (20))$ $(1+cos(2.57(20))$ giving

$R \times \frac{1 + cos (2.57 (20))}{1 + cos (2.57 (20))} = \frac{12}{1 + cos (2.57 (20))}$ $R xx (1+cos(2.57(20)))/(1+cos(2.57(20))) =12/(1+cos(2.57(20)))$

But $\frac{1 + cos (2.57 (20))}{1 + cos (2.57 (20))} = 1$ $(1+cos(2.57(20))) /(1+cos(2.57(20))) =1$ giving

$R = \frac{12}{1 + cos (2.57 (20))}$ $R=12/(1+cos(2.57(20)))$

$R \approx 7.390$ $R~~7.390$ to 3 decimal places

This solution is based on $cos (2.57 \times 20)$ $cos(2.57xx20)$

'~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

Or, if you meant:
$R = \frac{12}{1 + cos (2.5720)}$ $R=12/(1+cos(2.5720))$

$R = 6.003$ $R=6.003$ to 3 decimal places

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(R + RCos (2,57 (20)) = 12), How to solve for R?

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