Sandra needs 4 1/4 cups of flour for one kind of cookie and 3 1/8 cups for another kind. How much would she need for both kinds?

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Sandra needs 4 1/4 cups of flour for one kind of cookie and 3 1/8 cups for another kind. How much would she need for both kinds?

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Answer 1 · 2016-12-14T13:25:22

$\frac{59}{8}$ $59/8$ or $7 \frac{3}{8}$ $7 3/8$ cups.

Explanation:

To solve this we must add: $4 \frac{1}{4} + 3 \frac{1}{8}$ $4 1/4 + 3 1/8$

First, we must convert the Mixed Fractions to Improper Fractions. To do this we must multiply each integer by the appropriate form of $1$ $1$ and then add this to the fraction:

$((\frac{4}{4} \times 4) + \frac{1}{4}) + ((\frac{8}{8} \times 3) + \frac{1}{8})$ $((4/4xx 4) + 1/4) + ((8/8 xx 3) + 1/8)$

$(\frac{16}{4} + \frac{1}{4}) + (\frac{24}{8} + \frac{1}{8})$ $(16/4 + 1/4) + (24/8 + 1/8)$

$\frac{17}{4} + \frac{25}{8}$ $17/4 + 25/8$

Next we must get each equation over a common denominator (in this case 8) by multiply the fraction by the appropriate form of $1$ $1$ so we can add the fractions:

$(\frac{2}{2} \times \frac{17}{4}) + \frac{25}{8}$ $(2/2 xx 17/4) + 25/8$

$\frac{34}{8} + \frac{25}{8}$ $34/8 + 25/8$

$\frac{34 + 25}{8}$ $(34 + 25)/8$

$\frac{59}{8}$ $59/8$

or

$\frac{56 + 3}{8}$ $(56 + 3)/8$

$\frac{56}{8} + \frac{3}{8}$ $56/8 + 3/8$

$7 + \frac{3}{8}$ $7 + 3/8$

$7 \frac{3}{8}$ $7 3/8$

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Sandra needs 4 1/4 cups of flour for one kind of cookie and 3 1/8 cups for another kind. How much would she need for both kinds?

1 Answer

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