Question

Suppose `f(x)=x^4-4x^2+2`. What is the average rate of change of the function on the interval [1.9, 2.1]?

Answer 1

`16.08`

Explanation:

The average rate of change is given by:

`(f(b)-f(a))/(b-a)`

`a= 1.9` , `b=2.1`

`(((2.1)^4-4(2.1)^2+2)-((1.9)^4-4(1.9)^2+2))/(2.1-1.9)`

`((3.8081)-(0.5921))/(0.2)=16.08`