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Tate has bag of golf balls 3 red, 5 blue, 2 yellow, and 2 green. What is the probability that he pulls out a red one, replaces it, and then pulls out another red one?

1 Answer

Nov 3, 2016

$\frac{3}{12} \times \frac{3}{12} = \frac{1}{16}$ $3/12 xx 3/12 = 1/16$

Explanation:

There are 12 golf balls, of which 3 are red.

The probability of drawing a red = $\frac{3}{12}$ $3/12$

The fact that the ball was replaced, means that the probability for drawing a red a second time is still $\frac{3}{12}$ $3/12$

$P (R R) = P (R) \times P (R) \leftarrow$ $P(R R) = P(R) xx P(R)" "larr$ read 'TIMES' as 'AND'

= $\frac{3}{12} \times \frac{3}{12} = \frac{1}{4} \times \frac{1}{4} = \frac{1}{16}$ $3/12 xx 3/12 = 1/4xx1/4 =1/16$

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