Question

The center of a circle is at (-2, 3) and it has a radius of 3. What is the equation of the circle?

Answer 1

`(x + 2)^2 + (y - 3)^2 = 9`

Explanation:

Standard Equation of a Circle:
`(x - h)^2 + (y - k)^2 = r^2`

where
`C: (h, k)`
`r` = radius

`(x - (-2))^2 + (y - 3)^2 = 3^2`

`=> (x + 2)^2 + (y - 3)^2 = 9`

Answer 2

`(x+2)^2 + (y-3)^2 = 9`

Explanation:

the standard form of the equation of a circle is

`(x-a)^2 + (y-b)^2 = r^2`
where (a , b) are the coords of the centre and r , the radius.

here (a , b ) = ( -2 , 3 ) and r = 3
substitute these values into the equation to obtain

`(x+2)^2 + (y-3)^2 = 9`