The circle has center at point (2, 5) and with radius 3, what is the equation of a circle?
1 Answer
Jan 30, 2016
(x -2)^2 + (y - 5 )^2 = 9(x−2)2+(y−5)2=9
Explanation:
The standard form for the equation of a circle is.
(x - a )^2 + (y - b)^2 = r^2 (x−a)2+(y−b)2=r2 where (a , b ) is the centre and r , the radius.
This question gives all the necessary information needed to
complete the equation , centre = (2 , 5 ) and r = 3
hence equation is :
(x - 2)^2 + (y - 5 )^2 = 9(x−2)2+(y−5)2=9
