The curve has a parametric equation of $x=(t^3)-12t$ and $y=3(t^2)$ , how would you find the two points the parameter t=2 crosses the curve?

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Answer 1 · 2017-10-07T22:43:41

We have parametric equations:

$x= t^3 - 12t$
$y = 3t^2$

When $t=2$ we have:

$x= 8 - 24 = -16$
$y = 3*4 \ \ \ \ = 12$

So, there is only one point associated with $t$ which has cartesian coordinates $(-16,12)$

The graph of the curve is as follows:

Steve M

The curve has a parametric equation of x=(t^3)-12tx=(t^3)-12t and y=3(t^2)y=3(t^2), how would you find the two points the parameter t=2 crosses the curve?