The gas in a container is at a pressure of 3.00 atm at 25°C. Directions on the container wam the user not to keep it in a place where the temperature exceeds 52°C. What would the gas pressure in the container be at 52°C?

1 Answer
Apr 13, 2017

The pressure is =3.27atm

Explanation:

We apply Gay Lussac's Law

P_1/T_1=P_2/T_2

The initial pressure, P_1=3.00atm

The initial temperature T_1=25+273=298K

The final temperature T_2=52+273=325K

The final pressure is

P_2=T_2/T_1*P_1

=325/298*3=3.27atm