The gas inside of a container exerts #15 Pa# of pressure and is at a temperature of #450 ^o K#. If the temperature of the gas changes to #240 ^oC# with no change in the container's volume, what is the new pressure of the gas?

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Answer 1 · 2017-04-20T05:52:20

The new pressure is #=17.1Pa#

We apply Gay Lussac's Law

#P_1/T_1=P_2/T_2#

Initial pressure is #P_1=15Pa#

Initial temperature is #T_1=450K#

Final temperature is #T_2=240+273=513K#

The final pressure is

#P_2=T_2/T_1*P_1=513/450*15=17.1Pa#