The gas inside of a container exerts #32 Pa# of pressure and is at a temperature of #50 ^o K#. If the temperature of the gas changes to #90 ^oK# with no change in the container's volume, what is the new pressure of the gas?

Question

1001 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-05-04T12:55:13

The new pressure is #=57.6Pa#

We apply Gay Lussac's Law

#P_1/T_1=P_2/T_2#

The initial pressure is #P_1=32Pa#

The initial temperature is #T_1=50K#

The final temperature is #T_2=90K#

The final pressure is

#P_2=T_2/T_1*P_1#

#=90/50*32#

#=57.6Pa#