The gas inside of a container exerts #9 Pa# of pressure and is at a temperature of #650 ^o K#. If the temperature of the gas changes to #220 ^oC# with no change in the container's volume, what is the new pressure of the gas?
1 Answer
Oct 27, 2016
Explanation:
#(p1)/"T1"# =#(p2)/"T2"#
#(9)/"650"# =#(p2)/"220"#
#p2# =#3.046 Pa#
