The half-life of Iodine-131 is 8 days. What mass of I-131 remains from an 8.0g sample after 2 half-lives?
1 Answer
Explanation:
The key to this problem lies with how the nuclear half-life of a radioactive isotope was defined.
For a given sample of a radioactive isotope, the time needed for half of the sample to undergo decay will give you that isotope's nuclear half-life.
This means that every passing of a half-life will leave you with half of the sample you started with.
Let's say that you start with a sample
A0⋅12=A02→ after one half-life
What about after the passing of another half-life?
A02⋅12=A04→ after two half-lives
What about after the passing of another half-life?
A04⋅12=A08→ after three half-lives
and so on. With every half-life that passes, your sample will be halved.
Mathematically, you can express this as
A=A0⋅12n , where
You know that your sample of iodine-131 has a half-life of
This means that here
A=A0⋅122=A04
Since you started with an
A=8 g⋅14=2 g