The STP volume of an ideal gas is #2.78# #m^3#. What is the pressure of the sample at #1.75# #m^3# and #27°C#?

1 Answer
Dec 22, 2015

#P_2=1.75 atm#

Explanation:

The initial conditions are:
STP means: #T_1=273K# and #P_1=1atm#
The volume of the gas is #V_1=2.78m^3#

Since the volume (#V_2=1.75m^3#) and temperature (#T_2=300K#) are changing at the same time, the new pressure could be found using:

#(P_1V_1)/(T_1)=(P_2V_2)/(T_2)#

#=>P_2= (P_1V_1)/(T_1)xx(T_2)/(V_2)=(1atmxx2.78cancel(m^3))/(273cancel(K))xx(300cancel(K))/(1.75cancel(m^3))=1.75 atm#