Use the Debye-Huckel equation to evaluate gamma_(pm)γ± for a "0.0200 mol/kg"0.0200 mol/kg "HCl"HCl solution, with methanol as the solvent, at 25^@ "C"25∘C and "1 atm"1 atm?
The answer is gamma_(pm) = 0.6304γ±=0.6304 . I am writing this answer because this equation is rather difficult to evaluate correctly.
The density of methanol at this TT and PP is "0.787 g/cm"^30.787 g/cm3 , while its dielectric constant is epsilon_r = 32.6εr=32.6 .
Main Equation:
ln gamma_(pm) = -|z_(+)z_(-)|(A I_m^"1/2")/(1 + BaI_m^"1/2")lnγ±=−|z+z−|AI1/2m1+BaI1/2m
Sub-Equations:
A = (2piN_A rho_A)^"1/2"(e^2/(4piepsilon_0 epsilon_(r,A)k_BT))^"3/2"A=(2πNAρA)1/2(e24πε0εr,AkBT)3/2
B = e((2N_arho_A)/(epsilon_0 epsilon_(r,A) k_B T))^"1/2"B=e(2NaρAε0εr,AkBT)1/2
Molal-scale Ionic Strength:
I_m = sum_i z_i^2 m_i = stackrel("If single strong electrolyte")overbrace(1/2 |z_(+)z_(-)|(nu_(+) + nu_(-)) m_i)
Assume a ~~ 3xx10^(-10) "m" , or 3 angstroms, the mean ionic radius (including the hydration sphere).
Definitions:
gamma_(pm) is the activity coefficient of a solution containing some set of strong electrolytes, ignoring ion pairing interactions.
nu_(+) (nu_(-) ) is the stoichiometric coefficient of the cation (anion).
z_(-) (z_(+) ) is the charge of the anion (cation).
m_i is the molality of the solute in "mol/kg" .
N_A is Avogadro's number, 6.022xx10^(23) "mol"^(-1) .
rho_A is the density of the solvent in "kg/m"^3 .
epsilon_0 = 8.854xx10^(-12) "C"^2"/N"cdot"m"^2 is the vacuum permittivity.
epsilon_(r,A) is the dielectric constant of the solvent, with no units.
k_B = 1.3807xx10^(-23) "J/K" is the Boltzmann constant.
T is the temperature in "K" .
e is the proton charge, 1.602xx10^(-19) "C"
The answer is
The density of methanol at this
Main Equation:
Sub-Equations:
Molal-scale Ionic Strength:
Assume
Definitions:
gamma_(pm) is the activity coefficient of a solution containing some set of strong electrolytes, ignoring ion pairing interactions.nu_(+) (nu_(-) ) is the stoichiometric coefficient of the cation (anion).z_(-) (z_(+) ) is the charge of the anion (cation).m_i is the molality of the solute in"mol/kg" .N_A is Avogadro's number,6.022xx10^(23) "mol"^(-1) .rho_A is the density of the solvent in"kg/m"^3 .epsilon_0 = 8.854xx10^(-12) "C"^2"/N"cdot"m"^2 is the vacuum permittivity.epsilon_(r,A) is the dielectric constant of the solvent, with no units.k_B = 1.3807xx10^(-23) "J/K" is the Boltzmann constant.T is the temperature in"K" .e is the proton charge,1.602xx10^(-19) "C"
1 Answer
From the definitions above, I will evaluate
Sub-Equation Evaluations
color(green)(A) = (2piN_A rho_A)^"1/2"(e^2/(4piepsilon_0 epsilon_(r,A)k_BT))^"3/2"
= (2pi(6.022xx10^(23) "mol"^(-1))("787 kg/m"^3))^"1/2"
[(1.602xx10^(-19) "C")^2/(4pi(8.854xx10^(-12) "C"^2"/N"cdot"m"^2)(32.6)(1.3807xx10^(-23) "J/K")("298.15 K"))]^"3/2"
= color(green)(3.8885) color(green)(("kg"/"mol")^"1/2")
color(green)(B) = e((2N_Arho_A)/(epsilon_0 epsilon_(r,A) k_BT))^"1/2"
= (1.602xx10^(-19) "C")
[(2(6.022xx10^(23) "mol"^(-1))("787 kg/m"^3))/((8.854xx10^(-12) "C"^2"/N"cdot"m"^2)(32.6)(1.3807xx10^(-23) "J/K")("298.15 K"))]^"1/2"
= color(green)(4.5245xx10^9) color(green)(("kg"/"mol")^"1/2" "m"^(-1))
Now that those crazy ones are out of the way, here's the fairly easy one. The molal-scale ionic strength is the measure of total ion concentration, basically. Here's how you could use the equation:
color(green)(I_m) = 1/2sum_i z_i^2 m_i
= 1/2[z_(+)^2m_(+) + z_(-)^2 m_(-)]
= 1/2[z_(+)^2 nu_(+)m_i + z_(-)^2nu_(-)m_i]
= 1/2[|z_(+)z_(-)|nu_(+)m_i + |z_(+)z_(-)|nu_(-)m_i]
= 1/2|z_(+)z_(-)|(nu_(+) + nu_(-))m_i
= 1/2|1*-1|(1+1)("0.0200 mol HCl"/"kg methanol") = color(green)("0.0200 mol HCl"/"kg methanol")
Main Equation Evaluation
Now that those are calculated, we can use them in the main equation to get
ln gamma_(pm) = -|z_(+)z_(-)|(A I_m^"1/2")/(1 + BaI_m^"1/2")
= -|1*1|
[(3.8885 ("kg"/"mol")^"1/2"("0.0200 mol"/"kg")^"1/2")/(1 + (4.5245xx10^9 ("kg"/"mol")^"1/2" "m"^(-1))(3xx10^(-10) "m")("0.0200 mol"/"kg")^"1/2")]
= -0.4614
Therefore, we finally have that:
color(blue)(gamma_(pm)) = e^(ln gamma_(pm)) = color(blue)(0.6304)