What are all the zeroes of $f (x) = (3 x - 5) (2 x + 7)$ $f(x) = (3x-5)(2x+7)$ ?

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Answer 1 · 2018-08-02T00:48:05

$x = \frac{5}{3}, - \frac{7}{2}$ $x=5/3, -7/2$

We can find the zeroes by setting the expression equal to zero:

$(3 x - 5) (2 x + 7) = 0$ $(3x-5)(2x+7)=0$

We can set both terms equal to zero to get

$3 x - 5 = 0 \Rightarrow 3 x = 5 \Rightarrow x = \frac{5}{3}$ $3x-5=0=>3x=5=>x=5/3$ and

$2 x + 7 = 0 \Rightarrow 2 x = - 7 \Rightarrow x = - \frac{7}{2}$ $2x+7=0=>2x=-7=>x=-7/2$

Hope this helps!

What are all the zeroes of f(x) = (3x-5)(2x+7)f(x)=(3x−5)(2x+7)f(x) = (3x-5)(2x+7)?