What are the coordinates of the center of the circle #x^2 + y^2 -8x -10y -8=0#?
1 Answer
May 17, 2016
Explanation:
Complete the squares for
#0 = x^2+y^2-8x-10y-8#
#= color(blue)(x^2-8x+16)+color(green)(y^2-10y+25)-49#
#= color(blue)((x-4)^2)+color(green)((y-5)^2)-7^2#
Add
#(x-4)^2+(y-5)^2 = 7^2#
This is in the form of the standard equation of a circle:
#(x-h)^2+(y-k)^2 = r^2#
with center
graph{((x-4)^2+(y-5)^2-7^2)((x-4)^2+(y-5)^2-0.06)=0 [-16.67, 23.33, -5.2, 14.8]}