Question

What are the critical points of `f(x) = 2x^3-3x^2-12x`?

Answer 1

The critical points are `-1` and `2`.

Explanation:

To find the critical points of a function, you must compute its first derivative, and then find its zeroes: the first derivative would be

`f'(x)=6x^2-6x-12=6(x^2-x-2)`

So. to find its zeros, we must look for the zeroes of `(x^2-x-2)`, which are `-1` and `2`. So, these are the critical points of `f(x)`.