What are the critical values, if any, of #f(x)= (x+1)^2 /(-x^2 - x)#? Calculus Graphing with the First Derivative Identifying Stationary Points (Critical Points) for a Function 1 Answer Sonnhard Jun 24, 2018 No critical values Explanation: Note that #(x+1)^2/(-x^2-x)=(x+1)^2/(-x(x+1))=-(x+1)/x=-1-1/x# for #xne -1# so #f'(x)=1/x^2ne 0# Answer link Related questions How do you find the stationary points of a curve? How do you find the stationary points of a function? How many stationary points can a cubic function have? How do you find the stationary points of the function #y=x^2+6x+1#? How do you find the stationary points of the function #y=cos(x)#? How do I find all the critical points of #f(x)=(x-1)^2#? Let #h(x) = e^(-x) + kx#, where #k# is any constant. For what value(s) of #k# does #h# have... How do you find the critical points for #f(x)=8x^3+2x^2-5x+3#? How do you find values of k for which there are no critical points if #h(x)=e^(-x)+kx# where k... How do you determine critical points for any polynomial? See all questions in Identifying Stationary Points (Critical Points) for a Function Impact of this question 1570 views around the world You can reuse this answer Creative Commons License