What are the intercepts of $- 10 x - 9 y = 25$ $-10x-9y=25$ ?

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Answer 1 · 2016-03-08T05:19:56

The intercepts are:

$x$ $x$ -intercept $(- \frac{5}{2}, 0)$ $(-5/2, 0)$

$y$ $y$ intercept $(0, \frac{25}{9})$ $(0, 25/9)$

Note: There are two type of intercepts , the $x$ $x$ and $y$ $y$

a) $x$ $x$ intercept, is when $y = 0$ $y = 0$

b) $y$ $y$ intercept, is when $x = 0$ $x = 0$ .

$- - - - - - - - - - - - - -$ $--------------$

To find the intercepts of $- 10 x - 9 y = 25$ $-10x -9y = 25$

1) Let's find $x$ $x$ intercept, $y = 0$ $y=0$

$- 10 x - 9 (0) = 25$ $-10x -9(0) = 25$

$- 10 x = 25$ $-10 x = 25 " "$ then solve for x

$x = - \frac{25}{10} = - \frac{5}{2}$ $x = -25/10 = -5/2$

x-intercepts $(- \frac{5}{2}, 0)$ $(-5/2 , 0)$

2) Let's find $y$ $y$ intercept, $x = 0$ $x= 0$

$- 10 (0) - 9 y = 25$ $-10(0) -9y = 25$

$- 9 y = - 25$ $-9y = -25$

$y = \frac{25}{9}$ $y = 25/9$

$y$ $y$ intercept $(0, \frac{25}{9})$ $(0, 25/9)$

What are the intercepts of −10x−9y=25-10x-9y=25?