What are the intercepts of $11 x - 43 y = 9$ $11x-43y=9$ ?

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Answer 1 · 2018-03-22T10:02:53

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$11 x - 43 y = 9$ $11x-43y=9$

Divide by 9 both sides

$\Rightarrow \frac{11 x}{9} - \frac{49 y}{9} = \frac{9}{9}$ $=>(11x)/9 - (49y)/9=9/9$

$\Rightarrow \frac{x}{\frac{9}{11}} - \frac{y}{\frac{9}{49}} = 1$ $=>x/(9/11)-y/(9/49)=1$

Its in the form $\frac{x}{a} + \frac{y}{b} = 1$ $x/a+y/b=1$

On equating , we get

$a = \frac{9}{11}$ $a=9/11$ which is the x-intercept

$b = \frac{9}{49}$ $b=9/49$ which is the y-intercept

What are the intercepts of 11x-43y=911x−43y=911x-43y=9?