What are the intercepts of $- 14 y + 4 x = 7$ $-14y+4x=7$ ?

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What are the intercepts of $- 14 y + 4 x = 7$ $-14y+4x=7$ ?

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Answer 1 · 2016-02-04T20:52:34

$y_{intercept} = - \frac{1}{2}$ $y_("intercept")=-1/2" "$ $x_{intercept} = 1 \frac{3}{4}$ $" "x_("intercept")=1 3/4$

Explanation:

Given: $- 14 y + 4 x = 7$ $" " -14y+4x=7$

Rewrite as: $14 y = 4 x - 7$ $" "14y=4x-7$

Divide both sides by 14

$y = \frac{4}{14} x - \frac{7}{14}$ $y=4/14x-7/14$

$y = \frac{2}{7} x - \frac{1}{2}$ $y=2/7x-1/2$ ...................(1)
'~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
The x-intercept is when the graph 'crosses' the x-axis
and it crosses the x-axis at $y = 0$ $y=0$

To find the x-intercept substitute $y = 0$ $y=0$ into equation (1)

$0 = \frac{2}{7} x - \frac{1}{2}$ $0=2/7x-1/2$

$\frac{2}{7} x = \frac{1}{2}$ $2/7x=1/2$

$x = \frac{7 \times 1}{2 \times 2} = \frac{7}{4} = 1 \frac{3}{4}$ $x=(7xx1)/(2xx2) = 7/4 = 1 3/4$

$x_{intercept} = 1 \frac{3}{4}$ $x_("intercept")=1 3/4$
'~~~~~~~~~~~~~~~~~~~~~~~~~~~~
The y-intercept is when the graph 'crosses' the y-axis' and it crosses the y-axis at $x = 0$ $x=0$

To find the y-intercept substitute $c = 0$ $c=0$ into equation (1)

$y = (\frac{2}{7} \times 0) - \frac{1}{2}$ $y=(2/7xx0)-1/2$

$y_{intercept} = - \frac{1}{2}$ $y_("intercept")=-1/2$
'~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
Tony B

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What are the intercepts of $- 14 y + 4 x = 7$ $-14y+4x=7$ ?

1 Answer

Explanation:

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What are the intercepts of −14y+4x=7-14y+4x=7?

1 Answer

Explanation:

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What are the intercepts of $- 14 y + 4 x = 7$ $-14y+4x=7$ ?