What are the intercepts of $2 x - 13 y = - 17$ $2x-13y=-17$ ?

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Answer 1 · 2017-09-30T16:07:01

$(0, \frac{17}{13})$ $(0,17/13)$ and $(- \frac{17}{2}, 0)$ $(-17/2,0)$

A y-axis intercept occurs on the axis when the x value is equal to 0. The same with the x-axis and the y value being equal to 0

So if we let x=0, we will be able to solve for the y value at the intercept.

$2 (0) - 13 y = - 17$ $2(0)-13y=-17$
$- 13 y = - 17$ $-13y=-17$
$y = \frac{- 17}{- 13}$ $y=(-17)/(-13)$
$y = \frac{17}{13}$ $y=17/13$

So the y-axis intercept occurs when x=0 and y=17/13 giving the co-ordinate.

$(0, \frac{17}{13})$ $(0,17/13)$

To find the x-axis intercept we do the same thing but let y=0.

$2 x - 13 (0) = - 17$ $2x-13(0)=-17$
$2 x = - 17$ $2x=-17$
$x = - \frac{17}{2}$ $x=-17/2$

The x-axis intercept occurs when y=0 and x=-17/2 giving the co-cordinate

$(- \frac{17}{2}, 0)$ $(-17/2,0)$

What are the intercepts of 2x−13y=−172x-13y=-17?