What are the intercepts of $-31x-4y=9$ ?

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Answer 1 · 2017-02-09T21:51:44

To find the intercepts you need to set the other variable to $0$ and solve for the intercept variable you are looking for:

Solution for y-intercept - set $x = 0$ and solve for $y$ :

$(-31 xx 0) - 4y = 9$

$0 - 4y = 9$

$-4y = 9$

$(-4y)/color(red)(-4) = 9/color(red)(-4)$

$(color(red)(cancel(color(black)(-4)))y)/cancel(color(red)(-4)) = -9/4$

$y = -9/4$ ; y-intercept is $-9/4$ or $(0. -9/4)$

Solution for x-intercept - set $y = 0$ and solve for $x$ :

$-31x - (4 xx 0) = 9$

$-31x - 0 = 9$

$-31x = 9$

$(-31x)/color(red)(-31) = 9/color(red)(-31)$

$(color(red)(cancel(color(black)(-31)))x)/cancel(color(red)(-31)) = -9/31$

$x = -9/31$ ; x-intercept is $-9/31$ or $(-9/31, 0)$

What are the intercepts of -31x-4y=9-31x-4y=9?