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What are the intercepts of $3 x + 2 y = 14$ $3x+2y=14$ ?

1 Answer

Jan 11, 2016

The intercepts are at
$XXX (0, 7)$ $color(white)("XXX")(0,7)$ (the y-intercept)
and
$XXX (\frac{14}{3}, 0)$ $color(white)("XXX")(14/3,0)$ (the x-intercept)

Explanation:

For all values on the Y-axis: $x = 0$ $x=0$
Replacing $x$ $x$ with $0$ $0$ in the given equation:
$XXX 3 (0) + 2 y = 14$ $color(white)("XXX")3(0)+2y=14$

$XXX \to y = 7$ $color(white)("XXX")rarr y=7$
So the y-intercept is $7$ $7$ (i.e. it is at $(0, 7)$ $(0,7)$ )

For all values on the X-axis: $y = 0$ $y=0$
Replacing $y$ $y$ with $0$ $0$ in the given equation:
$XXX 3 x + 2 (0) = 14$ $color(white)("XXX")3x+2(0)=14$

$XXX \to x = \frac{14}{3}$ $color(white)("XXX")rarr x= 14/3$
So the x-intercept is $\frac{14}{3}$ $14/3$ (i.e. it is at $(\frac{14}{3}, 0)$ $(14/3,0)$ )

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