What are the intercepts of $3 x - 5 y = 25$ $3x-5y=25$ ?

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Answer 1 · 2018-03-04T10:59:48

$x - intercept = \frac{25}{3}$ $x- "intercept" = 25/3$
$y - intercept = - 5$ $y- "intercept" = -5$

$3 x - 5 y = 25$ $3x-5y=25$

For finding $x$ $x$ -intercept , put $y = 0$ $y=0$ .

$\Rightarrow 3 x - 5 (0) = 25$ $=> 3x -5(0)=25$

$\Rightarrow 3 x = 25$ $=> 3x = 25$

$\Rightarrow x = \frac{25}{3}$ $=> x=25/3$

We got $x$ $x$ -intercept $= \frac{25}{3}$ $=25/3$ .

For finding $y$ $y$ -intercept , put $x = 0$ $x=0$ .

$\Rightarrow 3 (0) - 5 y = 25$ $=> 3(0)-5y=25$

$\Rightarrow - 5 y = 25$ $=> -5y=25$

$\Rightarrow y = - 5$ $=> y=-5$

We got $y$ $y$ -intercept $= - 5$ $=-5$ .

What are the intercepts of 3x−5y=253x-5y=25?