What are the intercepts of #3x-5y=25#?

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Answer 1 · 2018-03-04T10:59:48

#x- "intercept" = 25/3#
#y- "intercept" = -5#

#3x-5y=25#

For finding #x#-intercept , put #y=0#.

#=> 3x -5(0)=25#

#=> 3x = 25#

#=> x=25/3#

We got #x#-intercept #=25/3#.

For finding #y#-intercept , put #x=0#.

#=> 3(0)-5y=25#

#=> -5y=25#

#=> y=-5#

We got #y#-intercept #=-5#.