What are the intercepts of $3 x - 9 y = 25$ $3x-9y=25$ ?

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Answer 1 · 2016-07-06T08:42:15

$x = \frac{25}{3} = 8 \frac{1}{3} and y = \frac{25}{- 9} = - 2 \frac{7}{9}$ $x = 25/3 = 8 1/3 " and "y = 25/(-9) = -2 7/9$

To find the x-intercept, make y = 0.
$3 x - 9 (0) = 25$ $3x -9(0) = 25$

$x = \frac{25}{3} = 8 \frac{1}{3}$ $x = 25/3 = 8 1/3$

To find the y-intercept, make x = 0.

$3 (0) - 9 y = 25$ $3(0) -9y = 25$

$y = \frac{25}{- 9} = - 2 \frac{7}{9}$ $y = 25/(-9) = -2 7/9$

For the y intercept you can also change the equation into standard form , $y = m x + c$ $y = mx + c$

$3 x - 9 y = 25$ $3x -9y = 25$

$3 x - 25 = 9 y$ $3x- 25 = 9y$

$y = \frac{1}{3} x - \frac{25}{9} c = - \frac{25}{9}$ $y = 1/3x -25/9 " " c = -25/9$

What are the intercepts of 3x−9y=253x-9y=25?