What are the intercepts of #5x+3y=13#?

Question

2540 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-02-17T14:34:13

The y-intercept is #13/3# or #(0, 13/3)#

The x-intercept is #13/5# or #(13/5, 0)#

Using the cover-up method we will solve for the y-intercept by eliminating the #x# term and solving for #y#;

#3y = 13#

#(3y)/color(red)(3) = 13/color(red)(3)#

#(color(red)(cancel(color(black)(3)))y)/cancel(color(red)(3)) = 13/3#

#y = 13/3#

Therefore the y-intercept is #13/3# or #(0, 13/3)#

Using the cover-up method we will solve for the x-intercept by eliminating the #y# term and solving for #x#;

#5x = 13#

#(5x)/color(red)(5) = 13/color(red)(5)#

#(color(red)(cancel(color(black)(5)))x)/cancel(color(red)(5)) = 13/5#

#x = 13/5#

Therefore the x-intercept is #13/5# or #(13/5, 0)#