What are the intercepts of #-6y+8x=1#?

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Answer 1 · 2018-03-09T05:42:58

x-intercept #=(1/8)#

y-intercept #= -(1/6)#

#-6y + 8x = 1#

When y = 0,

#8x = 1# or x-intercept #=(1/8)#

When x = 0,

#-6y = 1# or y-intercept #= -(1/6)#

This can be verified from the graph below
graph{(8x-1)/6 [-10, 10, -5, 5]}