What are the intercepts of $7 y - 4 x = 18$ $7y-4x=18$ ?

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Answer 1 · 2018-04-13T19:26:29

$(0, \frac{18}{7}) (- \frac{9}{2}, 0)$ $(0,18/7) (-9/2,0)$

Put $x = 0 and y = 0$ $x=0 and y=0$ to find the relevant points

When $x = 0$ $x=0$ . $7 y = 18$ $7y=18$ so $y = \frac{18}{7}$ $y=18/7$

When $y = 0$ $y=0$ . $- 4 x = 18$ $-4x=18$ so $x = \frac{18}{- 4}$ $x=18/(-4)$ . = $- \frac{9}{2}$ $-9/2$

What are the intercepts of 7y-4x=187y−4x=187y-4x=18?